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What Is McGraw Hill Connect Answers?

McGraw Hill Connect is an online platform where students can execute their digital assessments and assignments with other coursework and text materials.

The software retains a healthy learning environment that helps to progress profoundly in academic life. As the main agenda of the McGraw Hill Education is to improve a student’s performance, the organized assessments are complex and challenging for a majority of the students.

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Useful Sums For McGraw Hill Connect Answers Projects

Q1. Determine whether the association between the two variables is positive or negative. The number of hours a college student spent studying in the past 24  hours and the number of hours the student spent sleeping in the past 24 hours.

Ans : The association between the number of hours a college student spent studying in the past 24 hours and the number of hours the student spent sleeping in the past 24 hours is negative.

Q2. Determine whether the correlation coefficient is an appropriate summary for the scatterplot and explain your reasoning.

graph
Ans : The correlation coefficient is appropriate because the variables have a weak linear relationship.

Q3. Price of eggs and milk: The following table presents the average price in dollars for a dozen eggs and a gallon of milk for each month from March through December 2009  . Use a TI- 84 calculator to answer the following.

Dozen EggsGallon of Milk
0.942.85
0.892.76
1.032.85
0.882.89
0.922.91
0.862.93
0.932.89
0.922.94
0.922.95
0.942.89

Part 1: Compute the least-squares regression line for predicting the price of milk from the price of eggs. Round the slope and y-intercept to at least four decimal places.

Ans : Regression line equation: y_hat= 3.0598-0.1883x

Part2: If the price of eggs differs by $0.35 from one month to the next, by how much would you expect the price of milk to differ? Round your answer to at least two decimal places.
Ans : The price of milk would differ by $−0.07

Part 3: Predict the price of milk in a month when the price of eggs is $1.86 . Round the answer to two decimal places.
Ans : The price of milk is predicted to be $2.71

Q4. Compute the least-squares regression equation for the given data set. Round the slope and
y – intercept to at least four decimal places.

xy
74
65
36
22
53

Ans : Regression line equation: y_hat=3.1977+0.1744x

Q5. Compute the least-squares regression line for predicting y from x given the following
summary statistics. Round the slope and y-intercept to at least four decimal places.
x_bar=45,000, Sx=2.3,y_bar=1350, Sy=105, r=-0.84

Ans : Regression line equation: y_hat=1727001-38.3478x

Q6. Find the area to the right of  9.236  under the chi-square distribution with 5 degrees of freedom.

Ans : The area to the right is 0.10

Q7. A sample of 25 one-year-old girls had a mean weight of 24.1 pounds with a standard deviation of 4.3 pounds. Assume that the population of weights is normally distributed. A pediatrician claims that the standard deviation of the weights of one-year-old girls is less than 7  pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the  alpha =0.05 level of significance.

State the appropriate null and alternate hypotheses.

Ans :

H0 : σ=7
H1 : σ<7

This hypothesis test is a left-tailed test.
Find the critical value. Round the answer to three decimal places.
Ans:- the critical value is 13.848
Compute the test statistic. Round the answer to three decimal places.
Ans:-
χ2=9.056
Determine whether to reject Ho.At the level alpha=0.05, reject the null hypothesis
.State a conclusion.
Ans:- There is enough evidence to conclude that the population standard deviation of the weights of one-year-old girls is less than 7  pounds.

Q8. A recent study examined the effects of carbon monoxide exposure on a group of construction workers. The following table presents the numbers of workers who reported
various symptoms, along with the shift (morning, evening,  or night) that they worked.
Test the hypothesis of independence. Use the alpha=0.05 level of significance and the P-
value method with the TI-84 Plus calculator. What do you conclude?

Morning ShiftEvening ShiftNight Shift
Influenza1518120
Headache32265
Weakness16116
Shortness of Breath71111

.State the null and alternate hypotheses.
Ans :
H0: The shift and reported symptoms are independent.
H1: The shift and reported symptoms are not independent. This hypothesis test is a right-tailed test.
Find the P-value. Round your answer to four decimal places.
Ans : The P-value is 0.0021 Determine whether to reject Ho
Ans : Reject the null hypothesis. State a conclusion.
Ans : There is enough evidence to conclude that shift and reported symptoms are not independent.

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